97213529 郭益銘 의 블로그 항목
누구에게나
select dog.Provider_no from provider dog
where dog.Provider_no not in
(select distinct Provider.Provider_no from
(
SELECT Provider.Provider_no,p1.Item_No
FROM Provide p1,Provider
where p1.Provider_no='001' and Provider.Provider_no not in
(SELECT provide.Provider_no FROM Provider INNER JOIN provide ON Provider.Provider_no = provide.Provider_no where p1.Item_no = provide.Item_no)
)
)